Lab day 2!!
At the end of the lab, our Fe was 6.4298 grams. So, 1.2968 grams of Fe reacted in the lab.
Fe(II) 1.2968gFe * 1molFe/55.85gFe * 1mol Cu/1molFe * 63.55gCu/1molCu =1.476gCu
Fe(III) 1.2968gFe* 1molFe/55.85gFe * 3molCu/2molFe * 63.55gCu/1molCu = 2.213gCu
No comments:
Post a Comment