Lewis Dot Structure/Electron placement
1. Use the valence electrons
2. Place the valence electrons around the symbol
EX: Nitrogen is 1s2 2s2 2p3, meaning that it has 5 valence electrons (Highest energy level=2, 2s2 & 2p3, 2+3 = 5)
This means that 5 electrons will need to be accounted for.
Bond length is the distance between two nuclei. Measurement between the radius of the bonding atoms is less than the sum of the radii added together.
More Complex Lewis Dot Problems...
Sulfur trioxide
SO3
Sulfur has 6 valence electrons
Oxygen has 6 valence electrons, but there are 3 oxygen, so 3x6=18
Sulfur valence + Oxygen valence = 24 e-
So we begin our structure...
O
l
O - S - O
And notice that there are three bonds, making six electrons accounted for. (2 per bond)
So that means out of our 24 e- we need to account for, 6 are taken care of just by bonds. However, there are still 18 e- that are unaccounted for. So we continue, adding electrons to the Oxygen...
. .
: O :
. . l . .
:O - S - O:
. . . .
HEY! It looks done. But it's not. Sure all 24 electrons are accounted for, but S only has 6 electrons, not 8. This means we can double bond an oxygen, and recognizing that there will be resonance, it will look like, and variations of this
. .
: O :
. . l . .
:O - S =O
. . . .
If you need a better tutorial, or a little more explanation, click here.
I like the link you put down there as well as the precise explanation you had. Nice work.
ReplyDeleteI agree with Ganon, this information was helpful so thank you!
ReplyDeleteGreat information; the diagrams really help with comprehension.
ReplyDelete