Q= Heat in Joules
M= Mass in grams
C= Specific Heat
ΔT= Change in Temperature
EXAMPLE:
Calculate the amount of energy in joules required to heat 454 grams of water from 5.4 degrees C to 98.6 degrees C. Calculate the amount of energy in calories, too.
Q=?
M=454 g
Tinitial=5.4 degrees C
Tfinal=98.6 degrees C
c= 4.184 J/gdegC
Q=454x4.184x(98.6-5.4)
Q=1.77x10^5 Joules or 177 KJ
https://www.youtube.com/watch?v=4RkDJDDnIss
http://www.wikihow.com/Calculate-Specific-Heat
http://chemistry.about.com/od/workedchemistryproblems/a/Specific-Heat-Example-Problem.htm
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