What is % Composition of C10H14O?
Calculate the mass of H in 25.4 g of C10H14O.
C= 10 x 12.01 = 120.1
H= 14 x 1.01 = 14.14
O= 1 x 16 = 16.00
120.1 + 14.14 + 16.00 = 150.24 g/mol
%C= (120.1/150.24)(100)= 79.94% C
%H= (14.14/150.24)(100)= 9.412% H
%O= (16.00/150.24)(100)= 10.65% O
(9.412%)(25.4 g)= 2.39 g H
MOLECULAR FORMULAS
-whole number multiple of empirical formula
- ratio of masses
-Can be the same as the empirical formula
EX: P4O10
EMPIRICAL FORMULAS
-lowest whole number ratio of elements in a compound
-start with % composition and work to moles
You did a great job summing up what we learned in class about empirical formula. The link and your examples really helped make it clear for me!
ReplyDeleteI really like that you clarified the formulas in such an easy way to understand.
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